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Voltage Drop and Nonlinear Loads
 

 

Subject - Voltage Drop and Nonlinear Loads

November 20, 2007
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Voltage Drop and Nonlinear Loads (First Approach)

 

It’s well known that in a balanced 3-phase 4-wire circuit, the current in the neutral wire is zero (this is because the neutral current is the vectorial sum of the phase currents, i.e: the sum of three vectors equal in magnitude whose angle between each vector is 120 degrees. The result is zero).

 

Since no current is present in the neutral wire, the circuit length to be taken into consideration for voltage drop (VD) calculations is the one way length between the source and the load.

 

Consider now the same balanced circuit, but where the major portion of the load consists of nonlinear loads (assume third-harmonics which is a particular case of nonlinear loads). Under this condition, the phase currents consist of the fundamental current superimposed with the third-harmonic current, whose magnitude is approximately 1/3 of the fundamental. The current in the neutral wire will be the sum of six vectors: the three vectors of the fundamental currents (whose sum, as stated above, is zero), and the three corresponding to the third-harmonic currents, which add algebraically, since they are in phase (3 x 120 degrees = 360 degrees, i.e.: 0 degrees, i.e.:  in phase). Therefore, the current in the neutral wire will be approximately 3 x 1/3 = 1, i.e. the same magnitude as the phase current. Logically, the neutral wire size will be the same as the phase wire size.

 

What will be the VD under this condition? Since the current in the neutral wire has approximately the same value as the phase current and both phase and neutral sizes are equal, it is apparent that the VD under this condition (balanced loads where the major portion of the load consists of third-harmonic currents) is twice the VD of the first condition (balanced loads with no nonlinear loads present).

 

Let’s now consider the same balanced circuit, but where the major portion of the load consists of nonlinear loads (assume third-harmonics plus other harmonics or, other than third harmonics). Under this condition, the phase currents consists of the fundamental current superimposed with the various harmonics currents components, and the neutral wire current can reach a maximum theoretical value of 1.73 times the value of the phase current.  The industry has adopted the practice to double the neutral (remember however that the minimum size permitted by the Code for paralleling phase or neutral conductors is 1/0).

 

And what will be the VD under this condition? On the one hand, the neutral current is 1.73 times the phase current (let’s approximate to 2 times). On the other hand, since the neutral was doubled, its impedance is half compared to the phase. This leads that the VD in the neutral wire has the same value as it is in the phase wire. So we can conclude that a practical way to calculate the VD under this condition (balanced loads where the major portion of the load consists of nonlinear currents) is to double the VD of the first condition (balanced loads with no nonlinear loads present).

 

From the above considerations we can conclude that in general, a practical way to calculate the VD of a balanced circuit where the major portion of the load consists of nonlinear loads is to calculate the VD of the same circuit without nonlinear loads and double this value.

 

Of course, the above considerations are basically intuitive. Let’s now do a detailed evaluation with  a group of feeders taken as an example and compare the results.

 

 

Voltage Drop and Nonlinear Loads (Detailed Evaluation)

 

First of all we begin by differentiating two types of nonlinear loads:

For the purpose of simplicity, two types of nonlinear loads will be examined: nonlinear loads that may contain the fundamental current (60Hz) and, let’s say, the full spectrum of its harmonics (which we will call nonlinear) and, loads that contain the fundamental

current and its third-harmonic (which will be called as third-harmonic).

 

To get a comprehensive assessment of the results, the feeder loads range from 16A to 350A. Two calculations will be performed  for each load.

 

The first group, for nonlinear loads  (feeders ID suffix is “_N”. The second group for third-harmonic loads (feeders ID suffix is “_H”. The first group includes also the industry practice relative to the neutral sizing for nonlinear loads. Also, though not evaluated here in detail, the Excel spreadsheet show the results of the feeders under analysis where no nonlinear loads are present (feeders ID w/o suffix).

 

Except for the industry practice results, all of the calculations were performed according to the applicable NEC 2005 requirements.

 

Common data to each of the feeders:

  • 208Y/120V system
  • Three-phase, four-wire
  • Balanced
  • Terminals rated at 75oC
  • Continuous load
  • OCPD: Fixed-trip inverse-time breaker
  • OCPD not listed for operation at 100%
  • Ambient temperature: 30oC
  • Neutral counts as a current-carrying conductor
  • Neutral current

= 1.73 x Phase Current (max. theoretical for nonlinear load)

= phase current for third-harmonic currents

  • Phase and  Neutral adjustment factor = 80% (bundling factor)
  • PF = 90%
  • Length: 100 ft
  • Max. VD: 5%
  • Conductor type: CU-THHN (from 12AWG to 750 kcmil)
  • Raceway type: EMT
  • Equipment grounding conductor to be considered
  • No harmonic filter is considered

 

Step-by-step calculations will be shown only for 16A, 40A, 160A and 250A feeders. For the rest of the feeders the results (based on a computer program) are displayed in the corresponding Excel spreadsheet.

 

1.  Nonlinear loads

Image 1

    • NEC calculation
      • Feeder F16_N  (16A)

1.1.1.1 Phase size:

  • OCPD = 1.25 x 16A = 20A
  • Phase size BAAF (Before Any Adjustment Factor): 12AWG

(6.53 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 30A = 24A

Since 24A > 20A (OCPD), 12AWG is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 2.44%

1.1.1.2 Neutral size:

  • Neutral current = 1.73 x 16A = 27.7A
  • Neutral size BAAF: 10AWG

(10.38 kcmil); (Based on terminations rated at 75oC)

  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 40A = 32A

Since 32A > 27.7A (neutral current), 10AWG is OK (before VD)

  • Resulting neutral VD (after applying appropriate formula) = 2.55%

1.1.1.3 Resulting VD: 5% (OK)

1.1.1.4 Equipment grounding conductor based on OCPD 20A = 12AWG

            (Since neutral kcmil > gnd. wire kcmil (6.53), no change is required in neutral size)

1.1.1.5 EMT size for (3-12AWG) + (1-10AWG) + (1-12AWG): 1/2 ´´

 

 

      • Feeder F40_N  (40A)

1.1.2.1 Phase size:

  • OCPD = 1.25 x 40A = 50A
  • Phase size BAAF (Before Any Adjustment Factor): 8AWG

(16.51 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 55A = 44A

The next std. OCPD acceptable is 45A, however since the current OCPD is 50A, it does not protect the 8AWG, therefore its size is increased to 6AWG (26.24 kcmil)

  • Resulting phase VD (after applying appropriate formula) = 1.56%

1.1.2.2 Neutral size:

  • Neutral current = 1.73 x 40A = 69.2A
  • Neutral size BAAF: 4AWG

(41.74 kcmil); (Based on terminations rated at 75oC)

  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 95A = 76A

Since 76A > 69.2A (neutral current), 4AWG is OK (before VD)

  • Resulting neutral VD (after applying appropriate formula) = 1.76%

1.1.2.3 Resulting VD: 3.3% (OK)

1.1.2.4 Equipment grounding conductor based on OCPD 50A = 10AWG

            (Since neutral kcmil > gnd. wire kcmil (10.38), no change is required in neutral size. However, as the phase size was increased from 16.51 kcmil to 26.24 kcmil, the gnd. wire kcmil must be increased in the same proportion, resulting that the gnd. kcmil = 26.24/16.51) x 10.38 kcmil = 16.50 kcmil, whose equivalent next std. size is 8AWG (16.51 kcmil). Again, since neutral kcmil > gnd. wire kcmil no change is required in neutral size)

1.1.2.5 EMT size for (3-6AWG) + (1-4AWG) + (1-8AWG): 1 ´´

 

 

      • Feeder F160_N  (160A)

1.1.3.1 Phase size:

  • OCPD = 1.25 x 160A = 200A
  • Phase size BAAF: 3/0AWG

(167.8 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 225A = 180A

On the one hand, 180A > 160A. On the other hand, since 180A < 800A, NEC considers the next higher std. OCP, (i.e: 200A) as adequate to protect the phase conductor.

Then, no phase size increase is necessary and 3/0AWG is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 1.25%

1.1.3.2 Neutral size:

  • Neutral current = 1.73 x 160A = 277A

Since this is a nonlinear load, the 70% demand factor above 200A is not

applicable in this case.

  • Neutral size BAAF: 300 kcmil  (Based on terminations rated at 75oC)
  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 320A = 256A

Since 256A < 277A (neutral current), the neutral size was increased to 350 kcmil.

  • Resulting neutral VD (after applying appropriate formula) = 1.31%

1.1.3.3 Resulting VD: 2.6% (OK)

1.1.3.4 Equipment grounding conductor based on OCPD 200A = 6AWG (26.24 kcmil)

            (Since neutral kcmil > gnd. wire kcmil (26.24), no change is required in neutral size)

1.1.3.5 EMT size for (3-3/0AWG) + (1-350 kcmil) + (1-6AWG): 2-1/2 ´´

 

1.1.4 Feeder F250_N  (250A)

1.1.4.1 Phase size:

  • OCPD = 1.25 x 250A = 312.5A; next higher std.: 350A
  • Phase size BAAF: 400kcmil (Based on terminations rated at 75oC)
  • Phase ampacity at 90oC after adjustment factor =  0.8 x 380A = 304A

On the one hand, 304A > 250A. On the other hand, since 304A < 800A, NEC considers the next higher std. OCP, (i.e: 350A) as adequate to protect the phase conductor.

Then, no phase size increase is necessary and 400 kcmil is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 1.10%

1.1.4.2 Neutral size:

  • Neutral current = 1.73 x 250A = 432.5A

Since this is a nonlinear load, the 70% demand factor above 200A is not

applicable in this case.

  • Neutral size BAAF: 700 kcmil  (Based on terminations rated at 75oC)
  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 520A = 416A

Since 416A < 432.5A (neutral current), the neutral size was increased to 750 kcmil, whose ampacity at 90oC is 0.8 x 535A = 428A which still is less than the neutral current of 432.5A. Then, the next size should be used but, it is not available because we set a maximum size of 750 kcmil. Hence, the solution is to use two neutrals in parallel, each sized for a (neutral) current of 432.5A / 2 = 216.3A. Now we start over again the calculation for this figure.

  • (Each) neutral size BAAF: 4/0AWG
  • (Each) neutral ampacity at 90oC after adjustment factor = 0.8 x 260A = 208A (Note that the adjustment factor for five current-carrying conductors is still 80%).

Since 208A is < 216.3A (neutral current in each of the two paralleled neutral conductors), the neutral size was increased to the next size, i.e. 250 kcmil, whose ampacity at 90oC is 0.8 x 290A = 232A. On the one hand, 232A > 216.3A. On the other hand, the total neutral ampacity is 2 x 232A = 464A, which is > 350A (OCPD). Therefore, each neutral size is 250 kcmil (before VD).

  • Resulting neutral VD (after applying appropriate formula) = 1.28%

1.1.4.3 Resulting VD: 2.4% (OK)

1.1.4.4 Equipment grounding conductor based on OCPD 350A = 3AWG (52.62 kcmil)

            (Since neutral kcmil > gnd. wire kcmil (52.62), no change is required in neutral size)

1.1.4.5 EMT size for (3-400 kcmil) + (2-250 kcmil) + (1-3AWG): 3 ´´


 

 

2.  Third-Harmonic loads

Image 2

    • NEC calculation
      • Feeder F16_H (16A)

2.1.1.1 Phase size:

  • OCPD = 1.25 x 16A = 20A
  • Phase size BAAF (Before Any Adjustment Factor): 12AWG

(6.53 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 30A = 24A

Since 24A > 20A (OCPD), 12AWG is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 2.44%

2.1.1.2 Neutral size:

  • Neutral current = 16A
  • Neutral size BAAF: 14AWG
  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 25A = 20A

Since 20A > 16A (neutral current), 14AWG would be OK, however,

the minimum size being considered is 12AWG

  • Resulting neutral VD (after applying appropriate formula) = 4.9%

2.1.1.3 Resulting VD: 4.9% (OK)

2.1.1.4 Equipment grounding conductor based on OCPD 20A = 12AWG

            (Since neutral kcmil = gnd. wire kcmil (6.53), no change is required in neutral size)

2.1.1.5 EMT size for (3-12AWG) + (1-12AWG) + (1-12AWG): 1/2 ´´

 

 

2.1.2  Feeder F40_HH  (40A)

2.1.2.1 Phase size:

  • OCPD = 1.25 x 40A = 50A
  • Phase size BAAF (Before Any Adjustment Factor): 8AWG

(16.51 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 55A = 44A

The next std. OCPD acceptable is 45A, however since the current OCPD is 50A, it does not protect the 8AWG, therefore its size is increased to 6AWG (26.24 kcmil)

  • Resulting phase VD (after applying appropriate formula) = 1.56%

2.1.2.2 Neutral size:

  • Neutral current =  40A
  • Neutral size BAAF: 8AWG

(16.51 kcmil); (Based on terminations rated at 75oC)

  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 55A = 44A

Since 44A > 40A (neutral current), 8AWG is OK (before VD)

  • Resulting neutral VD (after applying appropriate formula) = 2.43%

2.1.2.3 Resulting VD: 4.0% (OK)

2.1.2.4 Equipment grounding conductor based on OCPD 50A = 10AWG

            (Since neutral kcmil > gnd. wire kcmil (10.38), no change is required in neutral size. However, as the phase size was increased from 16.51 kcmil to 26.24 kcmil, the gnd. wire kcmil must be increased in the same proportion, resulting that the gnd. kcmil = 26.24/16.51) x 10.38 kcmil = 16.50 kcmil, whose equivalent next std. size is 8AWG (16.51 kcmil). Again, since neutral kcmil = gnd. wire kcmil no change is required in neutral size)

2.1.2.5 EMT size for (3-6AWG) + (1-8AWG) + (1-8AWG): ¾ ´´

 

2.1.3    Feeder F160_H_H  (160A)

2.1.3.1 Phase size:

  • OCPD = 1.25 x 160A = 200A
  • Phase size BAAF: 3/0AWG

(167.8 kcmil); (Based on terminations rated at 75oC)

  • Phase ampacity at 90oC after adjustment factor =  0.8 x 225A = 180A

On the one hand, 180A > 160A. On the other hand, since 180A < 800A, NEC considers the next higher std. OCP, (i.e: 200A) as adequate to protect the phase conductor.

Then, no phase size increase is necessary and 3/0AWG is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 1.25%

2.1.3.2 Neutral size:

  • Neutral current = 160A
  • Neutral size BAAF: 2/0AWG  (Based on terminations rated at 75oC)
  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 195A = 156A

Since 156A < 160A (neutral current), the neutral size was increased to 3/0AWG.

  • Resulting neutral VD (after applying appropriate formula) = 1.25%

2.1.3.3 Resulting VD: 2.5% (OK)

2.1.3.4 Equipment grounding conductor based on OCPD 200A = 6AWG (26.24 kcmil)

            (Since neutral kcmil > gnd. wire kcmil (26.24), no change is required in neutral size)

2.1.3.5 EMT size for (3-3/0AWG) + (1-3/0AWG) + (1-6AWG): 2 ´´

 

2.1.4 Feeder F250_HH  (250A)

2.1.4.1 Phase size:

  • OCPD = 1.25 x 250A = 312.5A; next higher std.: 350A
  • Phase size BAAF: 400kcmil (Based on terminations rated at 75oC)
  • Phase ampacity at 90oC after adjustment factor =  0.8 x 380A = 304A

On the one hand, 304A > 250A. On the other hand, since 304A < 800A, NEC considers the next higher std. OCP, (i.e: 350A) as adequate to protect the phase conductor.

Then, no phase size increase is necessary and 400 kcmil is OK (before VD)

  • Resulting phase VD (after applying appropriate formula) = 1.10%

2.1.4.2 Neutral size:

  • Neutral current = 250A

Since this is a nonlinear load, the 70% demand factor above 200A is not

applicable in this case.

  • Neutral size BAAF: 250 kcmil  (Based on terminations rated at 75oC)
  • Neutral ampacity at 90oC after adjustment factor =  0.8 x 290A = 232A

Since 232A < 250A (neutral current), the neutral size was increased to 300 kcmil, whose ampacity at 90oC is 0.8 x 320A = 256A which is > 250A. Then, no further increase in neutral size is necessary and 300 kcmil is OK.

  • Resulting neutral VD (after applying appropriate formula) = 1.3%

2.1.4.3 Resulting VD: 2.4% (OK)

2.1.4.4 Equipment grounding conductor based on OCPD 350A = 3AWG (52.62 kcmil)

            (Since neutral kcmil > gnd. wire kcmil (52.62), no change is required in neutral size)

2.1.4.5 EMT size for (3-400 kcmil) + (1-300 kcmil) + (1-3AWG): 2-1/2 ´´

 

 

CONCLUSIONS:

  • In general, both for third harmonic and nonlinear loads, VD is approximately equal in the phase and in the neutral conductor for a given feeder.
  • In general, VD is approximately constant independently of the load (assuming the same feeder length).
  • Both for feeders w/o nonlinear loads or feeders whose third-harmonic currents are appreciable, it would seem at first glance that for circuits like the ones evaluated here (three-phase, four-wire, balanced), the neutral conductor size will be the same as the phase conductor size. However, as it has been demonstrated, this is not always true. The reason is that the phase conductor size is dependent (among other factors) on the OCPD value, while the neutral conductor depends (among other factors) on the neutral current.
  • The above conclusions are general.

 

Click on the following to view:

 

Jacob Mendelovici, P.E.

 

Mike Holt’s Comment: I sent the above to my “Electrical Engineer” buddy Mr. Eric Stromberg for his thoughts and they are as follows:

 

The voltage drop paper and calculations look good.  Mr. Medelovici did an admirable job.  The paper is clear.  The thought process is discernible.  The calculations pretty much are in line with some similar calculations I did a few years ago.

 

A few thoughts:

  • He states that 1/0 is the minimum for paralleling conductors.  310.4 exception No. 4 allows 2 AWG and larger to be paralleled under engineering supervision.

 

  • As with most calculations of this type, the results are conservative, or worst case.  It looks like the intended result here is to say that, worst case, the neutral should be doubled, the voltage drop should be considered to be in both directions.  This is a reasonable result when the loads are mostly non-linear, as described.

 

Best Regards,

Eric Stromberg, P.E.

 

 

 

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Comments
  • I am looking for 6 pole circuit breaker to meet the code for office furniture

    Bill Greenwald
    Reply to this comment

  • How do I comply to Article 605.7 Freestanding-Type Paritions when I have more than 6 to 8 circuits in the paritions per 2005 code when there is only 3 pole breaker available?

    Bill Greenwald
    Reply to this comment

  • This article is great and has the best explaination I have seen.

    There has been much said and debated over 3 phase 4 wire systems regarding the total load that the neutral sees.

    Has there been many studies on the use of 2 phase (west coast 1 phase) 3 wire systems and the load that the neutral sees under this condition.

    Could this be the cause of so any neutrals discolored to a pretty brown in residential and commerical 120/240 panels?

    Jerry

    Jerry Englin
    Reply to this comment

  • Awesome stuff Mike. Thanks for presenting the detailed analysis. Drills home the point well.

    Malcolm Hebert, PE
    Reply to this comment

  • This is as as good an analysis for calculating the effect of non linear loads on the neutral but I would not ry to attempt such presion based on these asumptions. For one, non linear frequencies are not equivalent to pure 60 cycle, therefore the square root of 3 as a calculating factor will yield varying inaccuracies. In non linear loads peak voltage is also not equivalent to peak 60 cycle-though RMS may or may not be equivalent-anyway your RMS meter will not read the true RMS because it is calibrated for pure 60 cycle. The third harmonic of 60 cycle is certainly not 60 cycle. Because Z varies with frequency VD is also highly problamatic in non linear loads. Nevertheless, a balanced pure resistive load will not affect calculations and will yield the same results as if there were no non linear loads on another circuit.

    Bob

    Bob
    Reply to this comment

  • In my opinion the 'harmonic disease' we are seeing more and more in our industry is preventable. But instead of insisting that manufacturers of equipment which produces harmonic effects being made to install filters to block the damaging high currents in neutrals, overheating circuit breakers, transformers etc. and as we see, causes twice as much voltage drop than was accounted for in older buildings, we are being told to double sizes of neutrals and increase feeder and branch circuit sizes to accommodate harmonic problems. For owners of older buildings that complied with Code for all the 'normal' loads expected this is an injustice. I think that UL should include harmonic testing in their procedures and where harmonics 'leak out' into the supply wiring, refuse to label the product.

    bill talbot
    Reply to this comment

  • Mike, I couldn't get the first two of the three spreadsheets to load. The link went to a calendar of events.

    Bill Bamford
    Reply to this comment

  • Mike, the last two links to Calculation results opens only your calendar. Otherwise the article is very practical.

    Mark Zeleny
    Reply to this comment

  • The foundation of any principle is essential. Unfortunately I don't get paid to do such detailed math. I will turn this over to my elec engineering student foreman, who will have a great appreciation for it, and I will utilize Eric's method of calculating VD using as few mathematical steps as possible! sincerely, Craig (remedial math) Monin

    Craig Monin
    Reply to this comment

  • THE LINK OPENS TO A SCHEDULE. THIS IS A VERRY GOOD PROGAM THAT MAKES IT EASIER TO CHECK AND SPECIFY WIRE SIZING IN DESIGNS.

    GEORGE RUMACHIK
    Reply to this comment

  • If there is no neutral current for in balanced load and for pure sinusoidal waveform, then the neutral voltagedrop is zero no matter what neutral sizing you have - or conductor length.

    Just thought I'd let you know.

    Chuck Miller

    Chuck Miller
    Reply to this comment

  • Mr. Holt-

    We have been specyfing around harmonic mitigating transformers & devices (Harmonics Limited) to eliminate the need for double neutrals & panel buses. These also would then eliminate the problem with voltage drop.

    Ed Gansberg
    Reply to this comment

  • I have found many problems with computer circuits powered from 3 phase wye circuits. The mother boards overheat from the voltage excessive drop. If you look at the current being drawn on these circuits with a power quality meter, you can find peaks of 27 amps on a 20 amp circuits that happen up to 30 times during a cycle. We have had good luck by supplying our computer systems with a single phase panel. we ussally put in a 30 amp 480volt circuit and use a transformer to make up our new power with a newly developed neutral. I am glad to see that someone has brought this to light.

    Gerry Clauss
    Reply to this comment

  • Mike.

    I think there is a fundamental mistake in the analysis for voltage drop. The fundamental and harmonics must be considered individually, not lumped together. In a balanced three-phase circuit, with harmonics, there will be no fundamental current flowing in the neutral, although there will be harmonic current. Therefore the voltage drop for the fundamental in the neutral will be zero. Likewise, only the fundamental current in the phase conductors can be considered when determining voltage drop, since only the voltage drop at 60 Hz is of concern. There will be voltage drops at each of the harmonic frequencies, of course, but these are of no concern.

    The rest of the analysis concerning wire size, based on total (harminic plus fundamental) current, is excellent.

    Jim Taylor
    Reply to this comment

  • I agree with Jim Taylor's original comment but would add one thing. The third harmonic current does cause a voltage drop in the neutral (and in the phase conductors) but the voltage drop does not reduce the fundamental voltage at the load.

    The voltage drop caused by third harmonic current is a third harmonic voltage. The harmonic voltage drop results in voltage distortion. If the harmonic voltage drop is more than 5%, then it may cause problems with sensitive loads.

    Jim Ghrist
    Reply to this comment


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