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Transformer Calculations - Based on the 2014 NEC  

 

By Mike Holt, NEC Consultant

An understanding of basic transformer facts and NEC requirements will help you avoid potentially tragic errors.

A transformer transfers electrical energy from one system to another by induction. Except for grounding and bonding connections, there’s no physical connection between the two systems. For this reason, the NEC refers to transformers as “separately derived systems.”

The ratio of the number of turns in the primary (supply) side to the number on the secondary (load) side determines how much the unit transforms the power supplied to it. This is a key concept in transformer theory and application.

Typically, a transformer raises or lowers the voltage. But isolation transformers don’t; they simply decouple two systems. Let’s cover some transformer basics before addressing NEC requirements.

 

Wye vs. Delta

Wye-configured transformers have one lead from each of three windings connected to a common point. The other leads from each of the windings are connected to the line conductors. A wye-configured secondary is often represented with a Y-shaped arrangement of the windings.

Delta-connected transformers have three transformer windings connected end-to-end with each other. The line conductors are connected to each point where two windings meet. This system is called a “delta” because when it’s drawn out it looks like a triangle (the Greek letter delta).

The terms “high-leg,” “wild-leg,” or “stinger-leg” are used to identify the conductor of a delta-connected system that has a nominal voltage rating of 208V to ground. The high-leg voltage is the vector sum of the voltage of transformers A and C1, or transformers B and C2, which equal (240V/2) x 1.732 = 208V for a 120/240V secondary.

If the actual voltage of the delta-connected system isn't 120/240V on the secondary, the actual high-leg voltage would = (line voltage/2) x 1.732

Question: What’s the actual voltage of the high-leg if the delta-configured secondary is 115/230V, three-phase?

(a) 115V      (b) 199V      (c) 230V      (d) 240V

Answer: (b) 199V

High-Leg Voltage = (Line Voltage/2) x 1.732

High-Leg Voltage = (230V/2) x 1.732

High-Leg Voltage = 199.18V

High-Leg Conductor Identification [110.15]

On a 4-wire, delta-connected, three-phase system, where the midpoint of one phase winding is grounded (high-leg system), the conductor with 208V to ground must be durably and permanently marked by an outer finish orange in color, or other effective means. Such identification must be placed at each point on the system where a connection is made if the neutral conductor is present [110.15, and 230.56].

When replacing equipment in existing facilities that contain a high-leg conductor, ensure the high-leg conductor is replaced in its original location. Prior to 1975, the high-leg conductor was required to terminate on the “C” phase of panelboards and switchboards. Failure to re-terminate the high-leg as it was in the existing installation can result in 120V circuits inadvertently connected to the 208V high-leg, with disastrous results.

 

Rating, voltage, current

  • Transformers are rated in kilovolt-amperes (kVA); 1 kilovolt-ampere = 1,000 volt-amperes (VA).
  • The voltage measured on the circuit conductors that supply the primary side is the primary line voltage. The voltage measured on the secondary side circuit conductors that feed the load is the secondary line voltage.
  • The single-phase formula for calculating the line current of a transformer is: I = VA/E. For three-phase, I = VA/(E x 1.732). Convert kVA to VA by multiplying kVA x 1,000.

With this background, you can more readily make sense of the NEC requirements for transformers.

 

Conductor Identification

Where the premises wiring system contains feeders supplied from more than one voltage system, each ungrounded conductor, at all termination, connection, and splice points, must be identified by phase or by line and system [215.12(C)].

Identification can be by color coding, marking tape, tagging, or other means approved by the authority having jurisdiction. The identification must be documented in a manner that’s readily available, or it must be permanently posted at each panelboard [215.12(C)(1)(a) and (b)].

Conductors with insulation that’s green (or green with one or more yellow stripes) can’t be used for an ungrounded or neutral conductor [250.119].

 

Overcurrent Protection Device (OCPD)

To protect the windings of a transformer against overcurrent, use the percentages listed in Table 450.3(B) and its applicable notes.

Article 450 is for the protection of the transformer windings, not the conductors supplying the transformer or leaving it. Where 125 percent of the primary current doesn’t correspond to a standard fuse or nonadjustable OCPD, you can use the next higher rating, as listed in 240.6(A); but only for currents of 9A or more.

 

Primary conductor sizing

Size primary conductors at least 125 percent of the continuous loads, plus 100 percent of the noncontinuous loads, based on the terminal temperature rating ampacities as listed in Table 310.15(B)(16), before any ampacity adjustment [210.19(A)(1)].

You must protect the conductors against overcurrent after ampacity adjustment, as specified in 310.15 [240.4]. You can use the next higher standard rating of OCPD (above the ampacity of the conductors being protected) if the OCPD rating doesn’t exceed 800A [240.4(B)].

Question: What size primary conductor can be used for a 45 kVA continuous loaded, three-phase, 480V transformer, where the primary OCPD is sized at 70A?

(a) 6 AWG      (b) 4 AWG      (c) 3 AWG      (d) 2 AWG

Answer: (b) 4 AWG

Step 1: Size the primary conductor at 125% of the primary current rating.

I = 45,000 VA/(480V x 1.732)

I = 54A

54A x 1.25 = 68A, 4 AWG, rated 70A at 60 DegrC, 110.14(C)(1)(a)(1)

Table 310.15(B)(16)

Step 2: Verify the conductors are protected per their ampacities [240.4]. A conductor rated 70A at 60 DegrC can be protected by a 70A primary OCPD.

 

Secondary conductor sizing

The ampacity of the secondary conductor must be at least the rating of the device supplied by the secondary conductors or the OCPD at the termination of the secondary conductors [240.21(C)(2)]. Assume the secondary conductors are intended to carry the full capacity of the transformer continuously.

Step 1: Determine the rating of the device supplied by the secondary conductors at 125 percent of the secondary rating [215.2(A)(1)(a)].

Step 2: Size the secondary conductors so their ampacity is at least that of the device they supply [240.21(C)].

Question: What size secondary conductor can be used for a 45 kVA continuous loaded, three-phase, 480-120/208V transformer?

(a) 2 AWG      (b) 1 AWG      (c) 1/0 AWG      (d) 2/0 AWG

Answer: (d) 2/0 AWG

Step 1: Determine the secondary current rating.

Secondary Current = Transformer VA/(Secondary Voltage x 1.732)

45 kVA x 1,000 = 45,000 VA

I = 45,000 VA/(208V x 1.732)

I = 125A

Step 2: Size the secondary OCPD for a continuous loading (125% of the secondary current rating) [215.3].

125A x 1.25 = 156A, 175A OCPD [240.6(A)]

Step 3: Size the secondary conductor so it has an ampacity at least that of the 175A secondary OCPD (from Step 2) [240.21(C)(2)].

Conductor rated 175A at 75DegrC [Table 310.15(B)(16), 110.14(C)(1)(b)(1)]

 

Grounding and bonding

You must install a system bonding jumper at the same location where the grounding electrode conductor terminates to the neutral point of a transformer. Size it per 250.102(C), based on the area of the secondary conductors [250.30(A)(1) and 250.28(D)(1)].

Question: What size system bonding jumper is required for a 45 kVA, three-phase, 480-120/208V transformer, when the secondary conductors are 2/0 AWG?

(a) 6 AWG      (b) 4 AWG      (c) 3 AWG      (d) 2 AWG

Answer: (b) 4 AWG [Table 250.102(C)(1)]

A grounding electrode conductor must connect the neutral point of a separately derived system to a grounding electrode of a type identified in 250.30(A)(4). Size the grounding electrode conductor per 250.66, based on the area of the ungrounded secondary conductor [250.30(A)(5)].

Question: What size grounding electrode conductor is required for a 45 kVA, three-phase, 480-120/208V transformer, when the secondary conductors are 2/0 AWG?

(a) 6 AWG      (b) 4 AWG      (c) 3 AWG      (d) 2 AWG

Answer: (b) 4 AWG [Table 250.66]

 

Can you be error-free?

If you think of transformers as being the electricity that goes through them, you’ll find it easier to apply transformer theory. Except for autotransformers, all transformers consist of two sets of interacting coils. The turns ratio of the primary set to the secondary set determines the degree to which the voltage is transformed (raised or lowered).

To keep from making grounding and bonding errors, remember there’s a difference between grounding and bonding.

Grounding is the connection to the earth. It’s accomplished with the grounding electrode and the grounding electrode conductor. This connection to earth won’t provide an effective ground-fault return path. That’s the role of proper bonding.

With transformers, a vital link in the bonding path is the system bonding jumper. It must be installed on the secondary of the transformer, either in the transformer or in the panel. The system bonding jumper completes the bonding path back to the source (the transformer secondary), to provide an effective fault current path.

 

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Comments
  • Great! Info.

    Badd Brad  July 15 2015, 1:32 am EDT

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